View Full Version : Puzzle #28
JP has extended his online adult novelty goods website to offer additional items.
He has 3 boxes delivered containing said goods.
The first box is marked Anal Destroyer, the second box is marked Merkins, and the third box is marked Merkins and Anal Destroyer.
Each of the boxes is labelled incorrecty. How could you label each box correctly if you were allowed to select only one online adult novelty good from one of the boxes?
:drink:
dvtimes
09-24-05, 04:01 PM
JP has extended his online adult novelty goods website to offer additional items.
He has 3 boxes delivered containing said goods.
The first box is marked Anal Destroyer, the second box is marked Merkins, and the third box is marked Merkins and Anal Destroyer.
Each of the boxes is labelled incorrecty. How could you label each box correctly if you were allowed to select only one online adult novelty good from one of the boxes?
:drink:
ouch.
needs thought.
dvtimes
09-24-05, 04:19 PM
The way I am doing it is to call the boxes am a m.
I take 1 from box am. If its an a then I call that box a, and if its a m I call it box m.
But that leaves me with two boxes. One should be box am and the other a or m.
So your left with box m, which must be box a or am.
And box a, which must be box m or box am.
Lets say box am is box m.
thus box a must be box am as it cannot be m
so box m is box a
dvtimes
09-24-05, 04:23 PM
JP has extended his online adult novelty goods website to offer additional items.
He has 3 boxes delivered containing said goods.
The first box is marked Anal Destroyer, the second box is marked Merkins, and the third box is marked Merkins and Anal Destroyer.
Each of the boxes is labelled incorrecty. How could you label each box correctly if you were allowed to select only one online adult novelty good from one of the boxes?
:drink:
so
take 1 from Merkins and Anal Destroyer.
Lets ay you took a Merkins
Merkins and Anal Destroyer is now Merkins
You are left with two boxes Merkins and Anal Destroyers
Anal Destroyers cannot be Anal Destroyers or Merkins. So you are only left with Merkins and Anal Destroyers.
So box Merkins must be Anal Destroyers.
morefodder
09-24-05, 07:58 PM
I cant work this one out .... :mad:
Mind you, whoeve marked the boxes up wrong is gonna find out where the anal destroyer goes and why its called that probably !! :atm:
dvtimes
09-24-05, 11:35 PM
I cant work this one out .... :mad:
Mind you, whoeve marked the boxes up wrong is gonna find out where the anal destroyer goes and why its called that probably !! :atm:
Do what I did.
Draw three boxes and lable them. You will find it easer just to use the first letters as i did. (A) (M) (AM)
Them on box (AM) decide if there is a (M) toy inside or an (A) toy. You already know that box cannot be the (AM) box.
In my example I chose toy (M). Thus you must now rename this box (M).
So you are left with two boxes (A) and (M).
You know one box must be box (A) and the other box (AM).
We know box (A) cannot have (A) toys in it, so you are left with (AM) toys (mixed).
So the last box (M) MUST be the (A) box.
morefodder
09-25-05, 03:30 PM
Do what I did.
Draw three boxes and lable them. You will find it easer just to use the first letters as i did. (A) (M) (AM)
Them on box (AM) decide if there is a (M) toy inside or an (A) toy. You already know that box cannot be the (AM) box.
In my example I chose toy (M). Thus you must now rename this box (M).
So you are left with two boxes (A) and (M).
You know one box must be box (A) and the other box (AM).
We know box (A) cannot have (A) toys in it, so you are left with (AM) toys (mixed).
So the last box (M) MUST be the (A) box.
Well cover me in eggs and flour, your goddamn right !!
Well done mate :crown:
Do what I did.
Draw three boxes and lable them. You will find it easer just to use the first letters as i did. (A) (M) (AM)
Them on box (AM) decide if there is a (M) toy inside or an (A) toy. You already know that box cannot be the (AM) box.
In my example I chose toy (M). Thus you must now rename this box (M).
So you are left with two boxes (A) and (M).
You know one box must be box (A) and the other box (AM).
We know box (A) cannot have (A) toys in it, so you are left with (AM) toys (mixed).
So the last box (M) MUST be the (A) box.
Sorted. PM me yer postal address and I'll ship you out a Anal Destroyer. :Penis
so
take 1 from Merkins and Anal Destroyer.
Lets ay you took a Merkins
Merkins and Anal Destroyer is now Merkins
You are left with two boxes Merkins and Anal Destroyers
Anal Destroyers cannot be Anal Destroyers or Merkins. So you are only left with Merkins and Anal Destroyers.
So box Merkins must be Anal Destroyers.
Your answer is not exactly what I was looking for.
However you logic is correct to solve the problem
Therefore I annouce you as :gold:
Shandy McAndy
09-25-05, 06:27 PM
Well cover me in eggs and flour
Then youll look like a pancake :crown:
Sorted. PM me yer postal address and I'll ship you out a Anal Destroyer. :Penis
might turn out cheaper to buy Alfie a coach or plane ticket rather than mailing him around.
might turn out cheaper to buy Alfie a coach or plane ticket rather than mailing him around.
you saying you think Alfie is an arse-bandit? :atm:
all i'm saying is he likes talking about gay-isms a lot. :D
he seems to talk about you and geezer mainly :confused: :p
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